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If the unit digit of 433 × 456 × 43N is (N+2), then what is the value of N?Options1836

Question

If the unit digit of 433 × 456 × 43N is (N+2), then what is the value of N?

Options: 1, 8, 3, 6

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Solution

The unit digit of a product depends on the unit digits of the numbers being multiplied.

  1. The unit digit of 433 is 3.
  2. The unit digit of 456 is 6.
  3. The unit digit of 43N is N.

When you multiply numbers, the unit digit of the product is determined by the unit digits of the numbers being multiplied.

So, let's multiply the unit digits of the given numbers:

3 * 6 = 18. The unit digit of 18 is 8.

So, the unit digit of the product 433 × 456 × 43N is 8.

According to the question, this unit digit is equal to (N+2).

So, we have the equation 8 = N + 2.

Solving for N, we get N = 8 - 2 = 6.

So, the value of N is 6.

This problem has been solved

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