If 40% increase in an amount in 4 years at SI. What will be the CI of Rs. 10000 after 2 years at the same rate?Rs.2200Rs.2300Rs.2400Rs.2100

First, let's find the rate of interest.

Given that the Simple Interest (SI) increases the amount by 40% in 4 years, the annual rate of interest would be 40%/4 = 10%.

Now, we need to find the Compound Interest (CI) for Rs. 10000 after 2 years at this rate.

The formula for CI is:

CI = P [(1 + r/n)^(nt) - 1]

Where: P = principal amount (the initial amount of money) r = annual interest rate (in decimal) n = number of times that interest is compounded per year t = time the money is invested for in years

In this case, P = Rs. 10000, r = 10% or 0.10, n = 1 (as it is compounded annually), and t = 2 years.

Substituting these values into the formula, we get:

CI = 10000 [(1 + 0.10/1)^(1*2) - 1] CI = 10000 [(1.10)^2 - 1] CI = 10000 [1.21 - 1] CI = 10000 * 0.21 CI = Rs. 2100

So, the Compound Interest of Rs. 10000 after 2 years at the same rate will be Rs. 2100.