If p q q r r pa , b and c ,p q q r r p       then the value of         1 a 1 b 1 c1 a 1 b 1 c     is(A) 1 (B) 0(C) 121 (D) 11

Question

If $p$ $q$ $q$ $r$ $r$ $pa$ , $b$ and $c$ , $p$ $q$ $q$ $r$ $r$ $p^{-1}$ $=$ $=$ $=$ $+$ $+$ $+$ then the value of $(1 + a)(1 + b)(1 + c)(1 - a)(1 - b)(1 - c)$ is\n $(A) 1$ $(B) 0$ $(C) 121$ $(D) 11$

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Solution

To find the value of 1 a 1 b 1 c + 1 a 1 b 1 c - 1, we can simplify the given expression step by step.

Given: p q q r r pa , b and c ,p q q r r p- = = =+ + +

Step 1: Substitute the given values into the expression: 1 a 1 b 1 c + 1 a 1 b 1 c - 1 = 1 (p q q r r pa) + 1 (b and c) - 1

Step 2: Simplify the expression: = p q q r r pa + b and c - 1

Step 3: Since the given expression is not fully defined, we cannot determine the exact value of the expression. Therefore, the answer is (E) Not enough information given.

Please note that the given expression is incomplete and lacks necessary information to provide a specific answer.

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If p q q r r pa , b and c ,p q q r r p       then the value of         1 a 1 b 1 c1 a 1 b 1 c     is(A) 1 (B) 0(C) 121 (D) 11

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