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Starting with 2 moles of PCl5 in 1 liter container 0.5 moles of PCl5 dissociates till equilibrium at 25oC, Equilibrium constant ‘KC’ is ____

Question

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Solution

The reaction for the dissociation of PCl5 can be written as:

PCl5 ⇌ PCl3 + Cl2

Initially, we have 2 moles of PCl5. At equilibrium, 0.5 moles of PCl5 have dissociated. Therefore, we have:

PCl5: 2 - 0.5 = 1.5 moles PCl3: 0 + 0.5 = 0.5 moles Cl2: 0 + 0.5 = 0.5 moles

The equilibrium constant Kc is given by the expression:

Kc = [PCl3][Cl2] / [PCl5]

Substituting the equilibrium concentrations into this expression gives:

Kc = (0.5 * 0.5) / 1.5 = 0.1667

Therefore, the equilibrium constant Kc is 0.1667.

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