Starting with 2 moles of PCl5 in 1 liter container 0.5 moles of PCl5 dissociates till equilibrium at 25oC, Equilibrium constant ‘KC’ is ____
Question
Solution 1
The reaction for the dissociation of PCl5 can be written as:
PCl5 ⇌ PCl3 + Cl2
Initially, we have 2 moles of PCl5. At equilibrium, 0.5 moles of PCl5 have dissociated. Therefore, we have:
PCl5: 2 - 0.5 = 1.5 moles PCl3: 0 + 0.5 = 0.5 moles Cl2: 0 + 0.5 = 0.5 moles
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