For the reaction PCl5(g) → PCl3(g) + Cl2(g) at298 K, Keq = 1.87 × 10-7, what is ΔrG ° and isthe reaction spontaneous?

Question

For the reaction PCl5(g) → PCl3(g) + Cl2(g) at298 K, Keq = 1.87 × 10-7, what is ΔrG ° and isthe reaction spontaneous?
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Solution 1

To find the ΔrG° (standard Gibbs free energy change) for the reaction, we can use the equation:

ΔrG° = -RT ln K

where: R is the universal gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (298 K in this case), and K is the equilibrium constant (Keq = 1.87 × 10^-7).

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