An isosceles right triangle has a perimeter of94+94 2​ inches. What is the length, in inches, of one leg of this triangle?

The question seems to be incorrectly formatted, but I'll assume you're asking about an isosceles right triangle (also known as a 45-45-90 triangle) with a perimeter of 94 inches.

In an isosceles right triangle, the two legs are of equal length and the hypotenuse is √2 times the length of one leg.

Let's denote the length of one leg as 'a'. So, the length of the hypotenuse is 'a√2'.

The perimeter of the triangle is the sum of the lengths of all its sides. So, we can set up the following equation:

a + a + a√2 = 94

Solving this equation will give us the length of one leg.

First, combine like terms:

2a + a√2 = 94

Next, we want to isolate 'a'. To do this, we can factor out 'a' from the left side of the equation:

a(2 + √2) = 94

Then, divide both sides of the equation by (2 + √2) to solve for 'a':

a = 94 / (2 + √2)

This gives us the length of one leg of the triangle.