Three persons A, B and C together have 51/-. B has 4/- less than A. C has got 5/- less than A. Find the money that C has.a.35/-b.20/-c.15/-d.50/-

Let's solve this step by step:

Step 1: Let's assume the amount of money that A has is x.

Step 2: According to the problem, B has 4/- less than A. So, B has (x - 4/-).

Step 3: The problem also states that C has 5/- less than A. So, C has (x - 5/-).

Step 4: The total amount of money that A, B, and C have together is 51/-. So, we can set up the following equation: x + (x - 4/-) + (x - 5/-) = 51/-.

Step 5: Simplify the equation: 3x - 9/- = 51/-.

Step 6: Add 9/- to both sides of the equation to isolate the term with x: 3x = 60/-.

Step 7: Divide both sides of the equation by 3 to solve for x: x = 20/-.

So, A has 20/-.

Step 8: To find the money that C has, subtract 5/- from the money that A has: 20/- - 5/- = 15/-.

So, C has 15/-. The answer is c.15/-.