x^2+x-3=0, solution set = _______Question 2Answera.{1, 3}b.{-3, -1}c.{-1.-3}d.{1, -3}

To find the solution set for the equation x^2 + x - 3 = 0, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / 2a.

For this equation, a = 1, b = 1, and c = -3.

Step 1: Calculate the value under the square root, b^2 - 4ac = (1)^2 - 41(-3) = 1 + 12 = 13.

Step 2: Calculate the two possible values for x using the quadratic formula:

x = [-1 + sqrt(13)] / 21 = 0.302 x = [-1 - sqrt(13)] / 21 = -3.302

So, the solution set for the equation x^2 + x - 3 = 0 is {0.302, -3.302}. This option is not listed in the provided choices.