Given the equation has point of intersection with the x axis atQuestion 2Select one:a.x = -2 and x = 4b.x = 2 and x = -4c.x = 2 and x = 4d.x = -2 and x = -4

Breakdown the Problem

1. Identify the equation that intersects with the x-axis. The points of intersection occur when $y = 0$.
2. Find the roots (values of $x$) where the equation equals zero.

Relevant Concepts

1. For a quadratic equation in standard form $ax^2 + bx + c = 0$, the points of intersection with the x-axis can be found using the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
2. The discriminant $D = b^2 - 4ac$ determines the nature of the roots. If $D > 0$, there are two distinct real roots.

Analysis and Detail

1. Without the explicit equation provided, we cannot calculate exact values. However, typically, we substitute the values of $x$ given in the options to see if $y = 0$ holds true.
2. Evaluate the provided options:
   • a. $x = -2$ and $x = 4$
   • b. $x = 2$ and $x = -4$
   • c. $x = 2$ and $x = 4$
   • d. $x = -2$ and $x = -4$

Verify and Summarize

1. To confirm the intersections, the roots must satisfy the equation $y = 0$ for each of the $x$ values given in the options.
2. Check each option against the standard forms of quadratic equations that can intersect the x-axis at those points.

Final Answer

As the specific equation is not provided, I cannot determine the exact option that describes the points of intersection. Please provide the specific equation or check with the given values to see which pairs correctly satisfy the condition $y = 0$. Typically, two distinct real roots will yield two intersections, and based on the common structure, options might often represent standard roots for typical quadratic equations.