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If 2.4 g of magnesium metal is completely burned in India, what percentage loss in weight of magnesium metal will increase?

Question

If 2.4 g of magnesium metal is completely burned in India, what percentage loss in weight of magnesium metal will increase?

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Solution

To analyze the burning of magnesium metal and calculate the percentage loss in weight, we must first consider the reaction that takes place when magnesium burns in the presence of oxygen.

1. ### Break Down the Problem

  1. Determine the molar mass of magnesium (Mg).
  2. Consider the balanced chemical reaction for magnesium combustion.
  3. Calculate the mass of magnesium oxide (MgO) formed.
  4. Find the loss in mass of magnesium after combustion.
  5. Calculate the percentage loss in weight.

2. ### Relevant Concepts

  • The balanced chemical equation for the burning of magnesium is: 2Mg+O22MgO 2 \text{Mg} + \text{O}_2 \rightarrow 2 \text{MgO}
  • Molar mass of magnesium (Mg) = 24.31 g/mol.
  • Molar mass of magnesium oxide (MgO) = 40.31 g/mol.

3. ### Analysis and Detail

  1. Calculate the moles of magnesium burned: Moles of Mg=2.4g24.31g/mol0.0987mol \text{Moles of Mg} = \frac{2.4 \, \text{g}}{24.31 \, \text{g/mol}} \approx 0.0987 \, \text{mol}

  2. Using the stoichiometry of the reaction, find the mass of MgO produced. Since 2 moles of Mg produce 2 moles of MgO, the moles of MgO formed will also be 0.0987 moles.

  3. Calculate the mass of MgO formed: Mass of MgO=Moles of MgO×Molar Mass of MgO=0.0987mol×40.31g/mol3.98g \text{Mass of MgO} = \text{Moles of MgO} \times \text{Molar Mass of MgO} = 0.0987 \, \text{mol} \times 40.31\, \text{g/mol} \approx 3.98 \, \text{g}

  4. Weight of magnesium used: 2.4 g.

  5. Since the mass does not disappear in combustion, the original mass will convert entirely to magnesium oxide. Hence, there is no actual "loss" of mass but rather a transformation of mass.

4. ### Verify and Summarize

  • The percentage loss in weight of magnesium is calculated as: Percentage Loss=(Initial MassFinal MassInitial Mass)×100 \text{Percentage Loss} = \left( \frac{\text{Initial Mass} - \text{Final Mass}}{\text{Initial Mass}} \right) \times 100
  • Here, there is no loss of magnesium itself since it entirely converts to magnesium oxide.

Final Answer

There is no percentage loss in weight of magnesium metal; the magnesium burns completely and forms magnesium oxide. The mass is conserved in the reaction, resulting in a transition from magnesium to magnesium oxide without any mass loss. Hence, the percentage loss in weight is 0%.

This problem has been solved

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