The magnitude of a vector is calculated using the Pythagorean theorem, which in the context of vectors translates to sqrt((A_x)^2 + (A_y)^2), where A_x and A_y are the i and j components of the vector respectively.

For vector A = 5.00i - 8.00j, A_x = 5.00 and A_y = -8.00.

So, the magnitude of vector A = sqrt((5.00)^2 + (-8.00)^2) = sqrt(25 + 64) = sqrt(89) = 9.43 (rounded to two decimal places).

So, the magnitude of vector A is 9.43.

Question

The magnitude of a vector is calculated using the Pythagorean theorem, which in the context of vectors translates to sqrt((A_x)^2 + (A_y)^2), where A_x and A_y are the i and j components of the vector respectively.

For vector A = 5.00i - 8.00j, A_x = 5.00 and A_y = -8.00.

So, the magnitude of vector A = sqrt((5.00)^2 + (-8.00)^2) = sqrt(25 + 64) = sqrt(89) = 9.43 (rounded to two decimal places).

So, the magnitude of vector A is 9.43.

Knowee AI · Accepted Answer

The magnitude of a vector is calculated using the Pythagorean theorem, which in the context of vectors translates to sqrt((A_x)^2 + (A_y)^2), where A_x and A_y are the i and j components of the vector respectively.

For vector A = 5.00i - 8.00j, A_x = 5.00 and A_y = -8.00.

So, the magnitude of vector A = sqrt((5.00)^2 + (-8.00)^2) = sqrt(25 + 64) = sqrt(89) = 9.43 (rounded to two decimal places).

So, the magnitude of vector A is 9.43.

Given vector A=5.00i - 8.00j . What is the magnitude of vector A?Group of answer choices9.43-3.003.6013.00

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Given vector A = 5.00i - 8.00j. What is the magnitude of vector A?

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