A vector of magnitude 10 m has an x-component of -5m. Its angle with positive x-axis isGroup of answer choices45o30o90o60o120o

The magnitude of a vector is given by the formula:

Magnitude = sqrt(x^2 + y^2)

Where x and y are the components of the vector. In this case, the magnitude is 10 and the x-component is -5. We can use these values to find the y-component:

10 = sqrt((-5)^2 + y^2) 100 = 25 + y^2 y^2 = 75 y = sqrt(75) = ±8.66

The angle θ between the vector and the positive x-axis is given by the formula:

θ = atan(y/x)

Where atan is the arctangent function. Since the x-component is negative and the y-component is positive, the vector is in the second quadrant. Therefore, the angle with the positive x-axis is:

θ = atan(8.66/-5) = -60 degrees

However, because the vector is in the second quadrant, the actual angle with the positive x-axis is:

180 - 60 = 120 degrees

So, the correct answer is 120 degrees.