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WAP in Java to input temperature in Fahrenheit and convert it in Celsius.         C= (F-32)*5/9

Question

WAP in Java to input temperature in Fahrenheit and convert it in Celsius.

C=(F32)×59 C = \frac{(F - 32) \times 5}{9}

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Solution

1. Break Down the Problem

We need to create a Java program that:

  1. Takes input of temperature in Fahrenheit from the user.
  2. Converts that temperature to Celsius using the formula C=(F32)×59 C = \frac{(F - 32) \times 5}{9} .
  3. Displays the converted temperature in Celsius.

2. Relevant Concepts

  • Input/Output in Java: Using Scanner class for taking user input.
  • Mathematical operations: Implementing the formula for conversion.
  • Data types: Using double for precise temperature representation.

3. Analysis and Detail

Here we will outline the main components of the Java code:

  • Import necessary classes.
  • Create a class with the main method.
  • Take input using Scanner.
  • Implement the conversion logic.
  • Print the result.

4. Verify and Summarize

After compiling and running the Java program, we will input a temperature in Fahrenheit and verify the output in Celsius by manually checking the calculation.

Java Program

Here’s the complete code implementing the above steps:

import java.util.Scanner;

public class TemperatureConverter {
    public static void main(String[] args) {
        // Create a Scanner object to take input
        Scanner scanner = new Scanner(System.in);
        
        // Prompt user for temperature in Fahrenheit
        System.out.print("Enter temperature in Fahrenheit: ");
        double fahrenheit = scanner.nextDouble();
        
        // Convert Fahrenheit to Celsius
        double celsius = (fahrenheit - 32) * 5 / 9;

        // Display the result
        System.out.printf("Temperature in Celsius: %.2f", celsius);
        
        // Close the scanner
        scanner.close();
    }
}

Final Answer

The Java program successfully takes temperature in Fahrenheit as input and converts it to Celsius using the formula provided, displaying the result to the user.

This problem has been solved

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