WAP in Java to input temperature in Fahrenheit and convert it in Celsius. C= (F-32)*5/9
Question
WAP in Java to input temperature in Fahrenheit and convert it in Celsius.
Solution
1. Break Down the Problem
We need to create a Java program that:
- Takes input of temperature in Fahrenheit from the user.
- Converts that temperature to Celsius using the formula .
- Displays the converted temperature in Celsius.
2. Relevant Concepts
- Input/Output in Java: Using
Scanner
class for taking user input. - Mathematical operations: Implementing the formula for conversion.
- Data types: Using
double
for precise temperature representation.
3. Analysis and Detail
Here we will outline the main components of the Java code:
- Import necessary classes.
- Create a class with the main method.
- Take input using
Scanner
. - Implement the conversion logic.
- Print the result.
4. Verify and Summarize
After compiling and running the Java program, we will input a temperature in Fahrenheit and verify the output in Celsius by manually checking the calculation.
Java Program
Here’s the complete code implementing the above steps:
import java.util.Scanner;
public class TemperatureConverter {
public static void main(String[] args) {
// Create a Scanner object to take input
Scanner scanner = new Scanner(System.in);
// Prompt user for temperature in Fahrenheit
System.out.print("Enter temperature in Fahrenheit: ");
double fahrenheit = scanner.nextDouble();
// Convert Fahrenheit to Celsius
double celsius = (fahrenheit - 32) * 5 / 9;
// Display the result
System.out.printf("Temperature in Celsius: %.2f", celsius);
// Close the scanner
scanner.close();
}
}
Final Answer
The Java program successfully takes temperature in Fahrenheit as input and converts it to Celsius using the formula provided, displaying the result to the user.
Similar Questions
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