Calculate the amount of heat (in J) to raise the temperature of 22.9 g of water from 4.3 o C to 31.9 oC.  (Cs, water = 4.18 J/g-oC)

Question

Calculate the amount of heat (in J) to raise the temperature of 22.9 g of water from 4.3 o C to 31.9 oC.  (Cs, water = 4.18 J/g-oC)
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

To calculate the amount of heat, we can use the formula:

q = m * Cs * ΔT

where:

  • q is the heat energy,
  • m is the mass of the substance,
  • Cs is the specific heat capacity of the substance, and
  • ΔT is the change in temperature.

Given:

  • m = 22.9 g,
  • Cs = 4.18 J/g-oC, and
  • ΔT = 31.9 oC - 4.3 o Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

Calculate the amount of heat (in J) to raise the temperature of 22.9 g of water from 4.3 o C to 31.9 oC.  (Cs, water = 4.18 J/g-oC)

The specific heat capacity of water is 4.184 J g -1 K -1 . Calculate the amount of heatrequired to raise the temperature of 1.00 g of water by 1.00 K

Suppose you mix 100.0 g of water at 22.8 oC with 75.0 g of water at 76.3  oC. What will be the final temperature of the mixed water, in oC?

The quantity of heat required to raise the temperature of 500 g of iron by 2°C, given that the specific heat capacity is 500 J/(kg °C), is:

Calculate the amount of heat required toraise the temperature of 2 moles of waterby 3°C. The specific heat capacity of wateris given as 4.18 − −1 1JK g

1/3