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If the probability that P will live 20 years is 1/2 and that B will live 20 years is 1/2, then what is the probability that both will live 20 years?

Question

If the probability that P will live 20 years is 12 \frac{1}{2} and that B will live 20 years is 12 \frac{1}{2} , then what is the probability that both will live 20 years?

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Solution

1. Break Down the Problem

  • Identify the individual probabilities:
    • Probability that P will live 20 years, P(P)=12 P(P) = \frac{1}{2}
    • Probability that B will live 20 years, P(B)=12 P(B) = \frac{1}{2}

2. Relevant Concepts

  • The events (P living for 20 years and B living for 20 years) are independent. Therefore, the joint probability of both P and B living for 20 years is given by: P(P and B)=P(P)×P(B) P(P \text{ and } B) = P(P) \times P(B)

3. Analysis and Detail

  • Using the individual probabilities: P(P and B)=(12)×(12) P(P \text{ and } B) = \left( \frac{1}{2} \right) \times \left( \frac{1}{2} \right)

4. Verify and Summarize

  • Performing the multiplication: P(P and B)=14 P(P \text{ and } B) = \frac{1}{4}

Final Answer

The probability that both P and B will live for 20 years is 14 \frac{1}{4} .

This problem has been solved

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