If L1 is regular L2 is unknown but L1-L2 is regular ,then L2 must be ans.Empty setRegularCFGDecidable Previous Marked for Review Next
Question
If L1 is regular L2 is unknown but L1-L2 is regular, then L2 must be
- ans.
- Empty set
- Regular
- CFG
- Decidable
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Marked for Review
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Solution
The statement "If L1 is regular L2 is unknown but L1-L2 is regular, then L2 must be" is a theoretical question in the field of formal languages and automata theory.
Here's a step-by-step explanation:
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L1 is a regular language. This means it can be expressed with a regular expression or a finite automaton.
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L2 is an unknown language. We don't know its properties.
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L1 - L2 is regular. This means that the language resulting from subtracting all the strings of L2 from L1 is a regular language.
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The question is asking what must L2 be for the above conditions to hold true.
The answer is that L2 can be any language. This is because the subtraction of any language from a regular language can result in a regular language. Therefore, L2 does not necessarily have to be regular, context-free, decidable, or an empty set. It can be any language.
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