A ball is projected vertically up with a velocity of 20 m/s. Its velocity when it reaches 15 m height is ______ m/s. (Take g = 10 m/s2)
Question
A ball is projected vertically up with a velocity of 20 m/s. Its velocity when it reaches 15 m height is ______ m/s. (Take g = 10 m/s²)
Solution
To solve this problem, we can use the equation of motion:
v² = u² - 2gh
where: v is the final velocity (which we're trying to find), u is the initial velocity (20 m/s in this case), g is the acceleration due to gravity (10 m/s²), and h is the height (15 m in this case).
Substituting the given values into the equation, we get:
v² = (20 m/s)² - 2*(10 m/s²)*(15 m) v² = 400 m²/s² - 300 m²/s² v² = 100 m²/s²
Taking the square root of both sides to solve for v, we get:
v = √(100 m²/s²) = 10 m/s
So, the velocity of the ball when it reaches a height of 15 m is 10 m/s.
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