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The diagram below is formed by 4 identical circles and a square. Each circle has a radius of 14 m. What is the area of the unshaded part? Take π as 3.14.

Question

The diagram below is formed by 4 identical circles and a square. Each circle has a radius of 14 m. What is the area of the unshaded part? Take π \pi as 3.14.

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Solution

1. Break Down the Problem

To find the area of the unshaded part, we need to:

  1. Calculate the area of the square.
  2. Calculate the total area of the four identical circles.
  3. Subtract the total area of the circles from the area of the square.

2. Relevant Concepts

  • Area of a square: Asquare=(side)2 A_{square} = (side)^2
  • Area of a circle: Acircle=πr2 A_{circle} = \pi r^2 Where r r is the radius of the circle.

3. Analysis and Detail

  1. Calculate the area of one circle: Acircle=πr2=3.14×(14)2 A_{circle} = \pi r^2 = 3.14 \times (14)^2 =3.14×196=615.44m2 = 3.14 \times 196 = 615.44 \, \text{m}^2

  2. Total area of four circles: Atotal_circles=4×Acircle=4×615.44=2461.76m2 A_{total\_circles} = 4 \times A_{circle} = 4 \times 615.44 = 2461.76 \, \text{m}^2

  3. Determine the side length of the square: Since the circles are arranged such that their sides touch the sides of the square, the side length of the square will be double the radius of one circle: side=2×r=2×14=28m side = 2 \times r = 2 \times 14 = 28 \, \text{m}

  4. Calculate the area of the square: Asquare=(side)2=(28)2=784m2 A_{square} = (side)^2 = (28)^2 = 784 \, \text{m}^2

  5. Calculate the area of the unshaded part: Aunshaded=AsquareAtotal_circles A_{unshaded} = A_{square} - A_{total\_circles} Aunshaded=7842461.76=1677.76m2 A_{unshaded} = 784 - 2461.76 = -1677.76 \, \text{m}^2

4. Verify and Summarize

The calculations indicate that the area of the circles exceeds the area of the square. Hence, this suggests that either the arrangement or proportion of the shapes is not consistent with the description, as the unshaded part cannot be negative.

Final Answer

The calculated area of the unshaded part is negative, indicating an inconsistency in the question's premise.

This problem has been solved

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