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he number of atoms per unit cell, coordination number, and atomic packing factor, for a FCC crystal are……………

Question

The number of atoms per unit cell, coordination number, and atomic packing factor, for a FCC crystal are……………

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Solution

To find the number of atoms per unit cell, coordination number, and atomic packing factor for a Face-Centered Cubic (FCC) crystal structure, we can analyze each aspect systematically.

1. Number of Atoms per Unit Cell

  • In a FCC structure, atoms are located at each corner of the cube and at the center of each face.
  • Each corner atom is shared by 8 adjacent unit cells, contributing 18 \frac{1}{8} of an atom to each unit cell.
  • Each face-centered atom is shared by 2 unit cells, contributing 12 \frac{1}{2} of an atom to the unit cell.

Calculating the total number of atoms:

  • 8 corner atoms contribute: 8×18=1 8 \times \frac{1}{8} = 1 atom.
  • 6 face-centered atoms contribute: 6×12=3 6 \times \frac{1}{2} = 3 atoms.

Thus, the total number of atoms per unit cell in a FCC structure is: Total atoms=1+3=4 \text{Total atoms} = 1 + 3 = 4

2. Coordination Number

  • The coordination number refers to the number of nearest neighbors surrounding an atom.
  • In the FCC structure, each atom touches 12 other atoms.

Thus, the coordination number for FCC is: Coordination Number=12 \text{Coordination Number} = 12

3. Atomic Packing Factor (APF)

  • The atomic packing factor is given by the ratio of the volume occupied by atoms in the unit cell to the volume of the unit cell itself.
  • The volume of one atom is given by Vatom=43πr3 V_{\text{atom}} = \frac{4}{3} \pi r^3 , where r r is the atomic radius.
  • In a FCC lattice, the relation between the atomic radius r r and the lattice parameter a a (edge length) is a=22r a = 2\sqrt{2}r .

Calculating the volume:

  • The volume of the unit cell is Vcell=a3=(22r)3=162r3 V_{\text{cell}} = a^3 = (2\sqrt{2}r)^3 = 16\sqrt{2}r^3 .
  • The volume occupied by the atoms in the unit cell is 4×Vatom=4×43πr3=163πr3 4 \times V_{\text{atom}} = 4 \times \frac{4}{3} \pi r^3 = \frac{16}{3} \pi r^3 .

Thus, the atomic packing factor (APF) can be calculated as: APF=Volume of atoms in unit cellVolume of unit cell=163πr3162r3=π320.7405 \text{APF} = \frac{\text{Volume of atoms in unit cell}}{\text{Volume of unit cell}} = \frac{\frac{16}{3} \pi r^3}{16\sqrt{2}r^3} = \frac{\pi}{3\sqrt{2}} \approx 0.7405

Final Answer

  1. Number of atoms per unit cell: 4
  2. Coordination number: 12
  3. Atomic Packing Factor (APF): Approximately 0.7405

This problem has been solved

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