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When the distance between two charged particles is doubled, theforce between them becomes

Question

When the distance between two charged particles is doubled, the force between them becomes

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Solution

Final Answer

When the distance between two charged particles is doubled, the force between them becomes one-fourth of its original value. This relationship is described by Coulomb's law, which states that the force F F between two charges q1 q_1 and q2 q_2 is inversely proportional to the square of the distance r r between them:

F=kq1q2r2 F = k \frac{|q_1 q_2|}{r^2}

If the distance r r is doubled (i.e., r r becomes 2r 2r ), the new force F F' can be expressed as:

F=kq1q2(2r)2=kq1q24r2=14F F' = k \frac{|q_1 q_2|}{(2r)^2} = k \frac{|q_1 q_2|}{4r^2} = \frac{1}{4} F

Thus, the force becomes one-fourth of the original force.

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