the magnitude of a charge on a particle which is moving with 10 metre per second is 2 coulomb now the velocity of the charge is doubled, then new charge is

To address the problem regarding the charge of a particle whose velocity is doubled, I'll begin by breaking down the necessary aspects.

1. Break Down the Problem

1. The initial charge $Q_1$ on the particle is given as 2 coulombs.
2. The initial velocity $v_1$ is 10 m/s.
3. The final velocity $v_2$ is double the initial, so $v_2 = 2 \times v_1 = 20$ m/s.
4. Determine if and how the charge changes when the velocity is altered.

2. Relevant Concepts

• In physics, the charge of a particle (in coulombs) is a property that does not depend on its velocity. The charge remains constant regardless of the speed of the particle, unless there is an external factor influencing the charge.

3. Analysis and Detail

1. The initial charge $Q_1$ is 2 C.
2. The charge does not change with velocity increase; hence after doubling the velocity, the charge remains $Q_2 = Q_1 = 2$ C.

4. Verify and Summarize

• Since we deduced that the charge of a particle remains constant regardless of the change in velocity, the calculations are verified.

Final Answer

The new charge after doubling the velocity is still 2 coulombs.