16 g of oxygen has same number of molecules as in 1 point(i) 16 g of CO(ii) 28 g of N2(iii) 14 g of N2(iv) 1.0 g of H2
Question
Solution 1
(i) 16 g of CO: The molar mass of CO (Carbon Monoxide) is 28 g/mol. So, 16 g of CO is 16/28 = 0.57 mol. According to Avogadro's law, one mole of any substance contains 6.022 x 10^23 molecules. So, 0.57 mol of CO contains 0.57 x 6.022 x 10^23 = 3.43 x 10^23 molecules.
(ii) 28 g of N2: The molar mass Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
16 g of oxygen has same number of molecules as in 1 point(i) 16 g of CO(ii) 28 g of N2(iii) 14 g of N2(iv) 1.0 g of H2
Q2How many moles of ammonia are produced from 0.60 moles of nitrogen? N2 (g) + 3 H2 (g) yields 2 NH3 (g)2 marks0.60.21.20.3
Which of the following molecules contain polar covalent bonds: CO, N2, NH3, NH4+, and HCl?
3 moles N2(g) is allowed to react with 6 moles of H2(g) to formNH3(g) in a close container. Find excess reagent and remainingmoles of excess reagent?
Hybridisation of (underlined atom) in given species is respectively :(I) [Fe(CO)5](II) [Ni(CO)4](III) BrF5(IV) N(SiH3)3