To determine which group represents the -M and +I effects respectively, let's analyze each option:

A) -NO2 and -CH=CH2: The -NO2 group is known to exhibit the -M effect, as it withdraws electron density from the attached atom or group. However, the -CH=CH2 group does not exhibit the +I effect, as it does not donate electron density.

B) -O- and -CH3: The -O- group does not exhibit the -M effect, as it does not withdraw electron density. However, the -CH3 group exhibits the +I effect, as it donates electron density.

C) -CHO and -O-: The -CHO group exhibits the -M effect, as it withdraws electron density. The -O- group does not exhibit the +I effect, as it does not donate electron density.

D) -COOH and -OH: The -COOH group exhibits the -M effect, as it withdraws electron density. The -OH group exhibits the +I effect, as it donates electron density.

Based on the analysis, the set of groups that represents the -M and +I effects respectively is option D: -COOH and -OH.

Question

To determine which group represents the -M and +I effects respectively, let's analyze each option:

A) -NO2 and -CH=CH2: The -NO2 group is known to exhibit the -M effect, as it withdraws electron density from the attached atom or group. However, the -CH=CH2 group does not exhibit the +I effect, as it does not donate electron density.

B) -O- and -CH3: The -O- group does not exhibit the -M effect, as it does not withdraw electron density. However, the -CH3 group exhibits the +I effect, as it donates electron density.

C) -CHO and -O-: The -CHO group exhibits the -M effect, as it withdraws electron density. The -O- group does not exhibit the +I effect, as it does not donate electron density.

D) -COOH and -OH: The -COOH group exhibits the -M effect, as it withdraws electron density. The -OH group exhibits the +I effect, as it donates electron density.

Based on the analysis, the set of groups that represents the -M and +I effects respectively is option D: -COOH and -OH.

Knowee AI · Accepted Answer

To determine which group represents the -M and +I effects respectively, let's analyze each option:

A) -NO2 and -CH=CH2: The -NO2 group is known to exhibit the -M effect, as it withdraws electron density from the attached atom or group. However, the -CH=CH2 group does not exhibit the +I effect, as it does not donate electron density.

B) -O- and -CH3: The -O- group does not exhibit the -M effect, as it does not withdraw electron density. However, the -CH3 group exhibits the +I effect, as it donates electron density.

C) -CHO and -O-: The -CHO group exhibits the -M effect, as it withdraws electron density. The -O- group does not exhibit the +I effect, as it does not donate electron density.

D) -COOH and -OH: The -COOH group exhibits the -M effect, as it withdraws electron density. The -OH group exhibits the +I effect, as it donates electron density.

Based on the analysis, the set of groups that represents the -M and +I effects respectively is option D: -COOH and -OH.

Which of following giving group is a set of –M and +I effect respectively.A –NO2 and –CH=CH2 B –O– and –CH3 C –CHO and –O– D –COOH and –OH

Question

Solution

Similar Questions

Upgrade your grade with Knowee