Air expands from 5 lit to 10 lit at 2 atm pressure. External work done is 10^n j . Find the value n
Question
Air expands from 5 lit to 10 lit at 2 atm pressure. External work done is j. Find the value
Solution
To find the value of n, we need to calculate the work done during the expansion of air. The work done can be determined using the formula:
Work = Pressure * Change in Volume
Given that the initial volume (V1) is 5 liters and the final volume (V2) is 10 liters, and the pressure (P) is 2 atm, we can substitute these values into the formula:
Work = 2 atm * (10 liters - 5 liters)
Simplifying the equation:
Work = 2 atm * 5 liters
Work = 10 atm * liters
Since the unit of work is atm * liters, we need to convert it to joules. 1 atm * liter is equal to 101.325 joules. Therefore:
Work = 10 atm * liters * 101.325 joules / (1 atm * liter)
Work = 1013.25 joules
So, the value of n is 3, since 10^n = 10^3 = 1000 joules.
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