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Air expands from 5 lit to 10 lit at 2 atm pressure. External work done is 10^n j . Find the value n

Question

Air expands from 5 lit to 10 lit at 2 atm pressure. External work done is 10n 10^n j. Find the value n n

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Solution

To find the value of n, we need to calculate the work done during the expansion of air. The work done can be determined using the formula:

Work = Pressure * Change in Volume

Given that the initial volume (V1) is 5 liters and the final volume (V2) is 10 liters, and the pressure (P) is 2 atm, we can substitute these values into the formula:

Work = 2 atm * (10 liters - 5 liters)

Simplifying the equation:

Work = 2 atm * 5 liters

Work = 10 atm * liters

Since the unit of work is atm * liters, we need to convert it to joules. 1 atm * liter is equal to 101.325 joules. Therefore:

Work = 10 atm * liters * 101.325 joules / (1 atm * liter)

Work = 1013.25 joules

So, the value of n is 3, since 10^n = 10^3 = 1000 joules.

This problem has been solved

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