The work done by a gas when its 0.5 mole at 27°C expands from 5 lit to 25 lit reversibly and isothermally is -x kJ. Find value of x ?
Question
Solution 1
To find the value of x, we can use the formula for the work done by a gas during an isothermal expansion:
Work = -nRT ln(V2/V1)
Where:
- n is the number of moles of the gas (0.5 mol in this case)
- R is the ideal gas constant (8.314 J/mol·K)
- T is the temperature in Kelvin (27°C = 300 K)
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