The DFA (Deterministic Finite Automaton) for accepting binary numbers whose decimal equivalent is divisible by 5 would have 5 states.

Here's why:

1. The states represent the remainder of the division by 5. Since 5 can give 5 possible remainders (0, 1, 2, 3, 4), we need 5 states.

2. The initial state is the state representing the remainder 0, because the number 0 is divisible by 5.

3. The final state is also the state representing the remainder 0, because we want to accept numbers divisible by 5.

4. The transitions are defined by the binary input. If we are in state q (representing remainder r) and we read a bit b, we go to state q' representing remainder (2*r + b) mod 5.

So, the correct answer is b.5.

Question

The DFA (Deterministic Finite Automaton) for accepting binary numbers whose decimal equivalent is divisible by 5 would have 5 states.

Here's why:

1. The states represent the remainder of the division by 5. Since 5 can give 5 possible remainders (0, 1, 2, 3, 4), we need 5 states.

2. The initial state is the state representing the remainder 0, because the number 0 is divisible by 5.

3. The final state is also the state representing the remainder 0, because we want to accept numbers divisible by 5.

4. The transitions are defined by the binary input. If we are in state q (representing remainder r) and we read a bit b, we go to state q' representing remainder (2*r + b) mod 5.

So, the correct answer is b.5.

Knowee AI · Accepted Answer

The DFA (Deterministic Finite Automaton) for accepting binary numbers whose decimal equivalent is divisible by 5 would have 5 states.

Here's why:

1. The states represent the remainder of the division by 5. Since 5 can give 5 possible remainders (0, 1, 2, 3, 4), we need 5 states.

2. The initial state is the state representing the remainder 0, because the number 0 is divisible by 5.

3. The final state is also the state representing the remainder 0, because we want to accept numbers divisible by 5.

4. The transitions are defined by the binary input. If we are in state q (representing remainder r) and we read a bit b, we go to state q' representing remainder (2*r + b) mod 5.

So, the correct answer is b.5.

r a DFA accepting binary numbers whose decimal equivalent is divisible by 5, how many sates the DFA would have.a.4 or 5b.5c.6d.4

Question

r a DFA accepting binary numbers whose decimal equivalent is divisible by 5, how many states the DFA would have.

Solution

Similar Questions

Upgrade your grade with Knowee