If the average of m numbers is n2 and that of n numbers is m2, find the average of (m+n) numbersnmm2nmnn2m
Question
If the average of m numbers is n2 and that of n numbers is m2, find the average of (m+n) numbers
n
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Solution
The question seems to be a bit jumbled, but I'll try to interpret it as best as I can.
If the average of m numbers is n^2, the sum of those m numbers is m*n^2.
Similarly, if the average of n numbers is m^2, the sum of those n numbers is n*m^2.
The sum of all m+n numbers is therefore mn^2 + nm^2.
To find the average of these m+n numbers, we divide the total sum by the number of terms, which is m+n.
So, the average of the m+n numbers is (mn^2 + nm^2) / (m+n).
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