Find the largest number which divides 62, 132, 237 to leave the same remainder in each case?a.32b.33c.34d.35
Question
Find the largest number which divides 62, 132, 237 to leave the same remainder in each case?
a. 32
b. 33
c. 34
d. 35
Solution
To find the largest number which divides 62, 132, 237 to leave the same remainder in each case, we need to find the HCF (Highest Common Factor) of the differences of these numbers.
First, let's find the differences:
132 - 62 = 70 237 - 132 = 105 237 - 62 = 175
Now, we find the HCF of 70, 105, and 175. The HCF of these numbers is 35.
So, the largest number which divides 62, 132, 237 to leave the same remainder in each case is 35. Therefore, the answer is (d) 35.
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