The equation you've given is 9x^2 + 4x = x.

First, let's simplify this equation by subtracting x from both sides to set the equation to equal zero. This gives us:

9x^2 + 4x - x = 0
9x^2 + 3x = 0

Now we can use the quadratic formula to solve for x. The quadratic formula is:

x = [-b ± sqrt(b^2 - 4ac)] / (2a)

In our equation, a = 9, b = 3, and c = 0.

Substituting these values into the quadratic formula gives us:

x = [-3 ± sqrt((3)^2 - 4*9*0)] / (2*9)
x = [-3 ± sqrt(9)] / 18
x = [-3 ± 3] / 18

So the solutions are x = 0/18 = 0 and x = -6/18 = -0.33 (rounded to the nearest hundredth).

So, the solutions for x are 0 and -0.33.

Question

The equation you've given is 9x^2 + 4x = x.

First, let's simplify this equation by subtracting x from both sides to set the equation to equal zero. This gives us:

9x^2 + 4x - x = 0
9x^2 + 3x = 0

Now we can use the quadratic formula to solve for x. The quadratic formula is:

x = [-b ± sqrt(b^2 - 4ac)] / (2a)

In our equation, a = 9, b = 3, and c = 0.

Substituting these values into the quadratic formula gives us:

x = [-3 ± sqrt((3)^2 - 4*9*0)] / (2*9)
x = [-3 ± sqrt(9)] / 18
x = [-3 ± 3] / 18

So the solutions are x = 0/18 = 0 and x = -6/18 = -0.33 (rounded to the nearest hundredth).

So, the solutions for x are 0 and -0.33.

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