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he maximum height of the graph of sin 2x is ___________. It is at x =_________.

Question

The maximum height of the graph of sin 2x is ___________.

It is at x = ___________.

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Solution

Understanding the Problem

  1. We need to determine the maximum height of the graph of the function sin(2x) \sin(2x) and the values of x x where this maximum height occurs.

Relevant Concepts

  1. The sine function, sin(x) \sin(x) , has a maximum value of 1. Therefore, the maximum height of sin(2x) \sin(2x) will also be 1.

Analysis and Detail

  1. The function sin(2x) \sin(2x) reaches its maximum height of 1 at specific points determined by the equation: 2x=π2+2kπ 2x = \frac{\pi}{2} + 2k\pi where k k is any integer (since the sine function is periodic).

    To find the corresponding values of x x , we solve for x x : x=π4+kπ x = \frac{\pi}{4} + k\pi where kZ k \in \mathbb{Z} .

Verify and Summarize

  1. Thus, the maximum height of the graph of sin(2x) \sin(2x) is 1, and this occurs at x=π4+kπ x = \frac{\pi}{4} + k\pi for any integer k k .

Final Answer

The maximum height of the graph of sin(2x) \sin(2x) is 1. It is at x=π4+kπ x = \frac{\pi}{4} + k\pi , where k k is any integer.

This problem has been solved

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