If X follows Binomial distribution with mean 3 and variance 2 , then P(X≥8) is equal to :1739183919392039

Question

If X follows Binomial distribution with mean 3 and variance 2 , then P(X≥8) is equal to :1739183919392039
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The question seems to be a bit confused. If X follows a binomial distribution with a mean of 3 and a variance of 2, we can find the parameters of the binomial distribution. The mean of a binomial distribution is np and the variance is np(1-p), where n is the number of trials and p is the probability Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

If X follows Binomial distribution with mean 3 and variance 2 , then P(X≥8) is equal to :1739183919392039

The variance for the binomial probability distribution isQuestion 7Select one:a.var(x) = P(1 - P)b.var(x) = nPc.var(x) = n(1 - P)d.var(x) = nP(1 - P)

Suppose X follows a binomial distribution with n=30 trials and p=0.5 probability of success . Find μₓ, the mean of X. Do not round your answer.2 points

In a Binomial Distribution, the mean and variance are equal.Review LaterTrueFalse

if the sum of the mean and variance of binomial distribution of 5trails is 4.8 ,find the corresponding pmf of the distribution

1/3