What will be the output of the following Python code?s={4>3, 0, 3-3}all(s)any(s)TrueFalse FalseTrue True True FalseFalse

The Python code you provided is not formatted correctly, but I will try to interpret it as best as I can.

It seems like you are creating a set s with three elements: 4>3, 0, and 3-3. Then, you are using the all() and any() functions on this set.

Here's the step-by-step explanation:

1. 4>3 is a comparison operation that checks if 4 is greater than 3. This is True.

2. 0 is considered as False in a boolean context in Python.

3. 3-3 results in 0, which is also considered as False in a boolean context in Python.

So, your set s is equivalent to {True, False, False}.

4. all(s) checks if all elements in the set are True. Since there are False elements in the set, all(s) will return False.

5. any(s) checks if any element in the set is True. Since there is at least one True element in the set, any(s) will return True.

Therefore, the output of the code will be False for all(s) and True for any(s).