The given Python code is:

```python
s={43, 0, 3-3}
all(s)
any(s)
```

Let's break it down:

1. `s={43, 0, 3-3}`: This line is creating a set `s`. The set contains three elements: `43`, `0`, and `3-3`. The `43` is a comparison operation which will return `True` because 4 is greater than 3. `3-3` is a subtraction operation which will return `0`. So, the set `s` will be `{True, 0, 0}`.

2. `all(s)`: The `all()` function returns `True` if all items in an iterable are true, otherwise it returns `False`. In the set `s`, not all items are true (there are two `0` which is considered as `False` in Python), so `all(s)` will return `False`.

3. `any(s)`: The `any()` function returns `True` if at least one item in an iterable is true, otherwise it returns `False`. In the set `s`, there is one `True`, so `any(s)` will return `True`.

So, the output of the given Python code will be `False` for `all(s)` and `True` for `any(s)`.

Question

The given Python code is:

```python
s={4>3, 0, 3-3}
all(s)
any(s)
```

Let's break it down:

1. `s={4>3, 0, 3-3}`: This line is creating a set `s`. The set contains three elements: `4>3`, `0`, and `3-3`. The `4>3` is a comparison operation which will return `True` because 4 is greater than 3. `3-3` is a subtraction operation which will return `0`. So, the set `s` will be `{True, 0, 0}`.

2. `all(s)`: The `all()` function returns `True` if all items in an iterable are true, otherwise it returns `False`. In the set `s`, not all items are true (there are two `0` which is considered as `False` in Python), so `all(s)` will return `False`.

3. `any(s)`: The `any()` function returns `True` if at least one item in an iterable is true, otherwise it returns `False`. In the set `s`, there is one `True`, so `any(s)` will return `True`.

So, the output of the given Python code will be `False` for `all(s)` and `True` for `any(s)`.

Knowee AI · Accepted Answer

The given Python code is:

```python
s={4>3, 0, 3-3}
all(s)
any(s)
```

Let's break it down:

1. `s={4>3, 0, 3-3}`: This line is creating a set `s`. The set contains three elements: `4>3`, `0`, and `3-3`. The `4>3` is a comparison operation which will return `True` because 4 is greater than 3. `3-3` is a subtraction operation which will return `0`. So, the set `s` will be `{True, 0, 0}`.

2. `all(s)`: The `all()` function returns `True` if all items in an iterable are true, otherwise it returns `False`. In the set `s`, not all items are true (there are two `0` which is considered as `False` in Python), so `all(s)` will return `False`.

3. `any(s)`: The `any()` function returns `True` if at least one item in an iterable is true, otherwise it returns `False`. In the set `s`, there is one `True`, so `any(s)` will return `True`.

So, the output of the given Python code will be `False` for `all(s)` and `True` for `any(s)`.

What will be the output of the following Python code?s={4>3, 0, 3-3}all(s)any(s)

Question

What will be the output of the following Python code?

Solution

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