To realize a full adder using NAND gates, we need to understand the logic behind a full adder and then determine the number of NAND gates required.

A full adder is a combinational circuit that adds three input bits (A, B, and Cin) and produces two output bits (Sum and Cout). The Sum bit represents the sum of the three inputs, while the Cout bit represents the carry generated during the addition.

To implement a full adder using NAND gates, we can use the following logic:

1. First, we need to implement the XOR gate using NAND gates. The XOR gate produces a high output (1) when the number of high inputs is odd. We can achieve this by connecting two NAND gates in series and then connecting their outputs to another NAND gate in parallel. This configuration will give us the XOR gate using NAND gates.

2. Next, we need to implement the AND gate using NAND gates. The AND gate produces a high output (1) only when all inputs are high. We can achieve this by connecting two NAND gates in series and then connecting their outputs to another NAND gate in series. This configuration will give us the AND gate using NAND gates.

3. Now, we can use the XOR and AND gates to implement the full adder. We need to connect the inputs A, B, and Cin to the XOR gates to calculate the Sum bit. We also need to connect the inputs A, B, and Cin to the AND gates to calculate the Cout bit. Finally, we need to connect the outputs of the XOR and AND gates to another set of XOR and AND gates to calculate the final Sum and Cout bits.

Based on this logic, we can determine the number of NAND gates required. By analyzing the circuit, we can see that we need a total of 6 NAND gates to implement a full adder using NAND gates.

Therefore, the correct answer is option c. 6-NAND gates only.

Question

To realize a full adder using NAND gates, we need to understand the logic behind a full adder and then determine the number of NAND gates required.

A full adder is a combinational circuit that adds three input bits (A, B, and Cin) and produces two output bits (Sum and Cout). The Sum bit represents the sum of the three inputs, while the Cout bit represents the carry generated during the addition.

To implement a full adder using NAND gates, we can use the following logic:

1. First, we need to implement the XOR gate using NAND gates. The XOR gate produces a high output (1) when the number of high inputs is odd. We can achieve this by connecting two NAND gates in series and then connecting their outputs to another NAND gate in parallel. This configuration will give us the XOR gate using NAND gates.

2. Next, we need to implement the AND gate using NAND gates. The AND gate produces a high output (1) only when all inputs are high. We can achieve this by connecting two NAND gates in series and then connecting their outputs to another NAND gate in series. This configuration will give us the AND gate using NAND gates.

3. Now, we can use the XOR and AND gates to implement the full adder. We need to connect the inputs A, B, and Cin to the XOR gates to calculate the Sum bit. We also need to connect the inputs A, B, and Cin to the AND gates to calculate the Cout bit. Finally, we need to connect the outputs of the XOR and AND gates to another set of XOR and AND gates to calculate the final Sum and Cout bits.

Based on this logic, we can determine the number of NAND gates required. By analyzing the circuit, we can see that we need a total of 6 NAND gates to implement a full adder using NAND gates.

Therefore, the correct answer is option c. 6-NAND gates only.

Knowee AI · Accepted Answer