The problem seems to be about the volumes of similar figures. In similar figures, the ratio of their volumes is the cube of the ratio of their corresponding lengths.

From the problem, we know that the ratio of the volumes of the two cones is V1/V2 = 64.

Since the figures are similar, the ratio of their corresponding lengths is the cube root of the ratio of their volumes. So, the ratio of their lengths is cube root of 64, which is 4.

This means that the larger cone is 4 times bigger than the smaller one in all dimensions.

Therefore, the volume of the larger cone (V2) is 4^3 = 64 times the volume of the smaller cone (V1).

Given that the volume of the smaller cone (V1) is 1 m^3, the volume of the larger cone (V2) is 64 * 1 m^3 = 64 m^3.

Question

The problem seems to be about the volumes of similar figures. In similar figures, the ratio of their volumes is the cube of the ratio of their corresponding lengths.

From the problem, we know that the ratio of the volumes of the two cones is V1/V2 = 64.

Since the figures are similar, the ratio of their corresponding lengths is the cube root of the ratio of their volumes. So, the ratio of their lengths is cube root of 64, which is 4.

This means that the larger cone is 4 times bigger than the smaller one in all dimensions.

Therefore, the volume of the larger cone (V2) is 4^3 = 64 times the volume of the smaller cone (V1).

Given that the volume of the smaller cone (V1) is 1 m^3, the volume of the larger cone (V2) is 64 * 1 m^3 = 64 m^3.

Knowee AI · Accepted Answer

The problem seems to be about the volumes of similar figures. In similar figures, the ratio of their volumes is the cube of the ratio of their corresponding lengths.

From the problem, we know that the ratio of the volumes of the two cones is V1/V2 = 64.

Since the figures are similar, the ratio of their corresponding lengths is the cube root of the ratio of their volumes. So, the ratio of their lengths is cube root of 64, which is 4.

This means that the larger cone is 4 times bigger than the smaller one in all dimensions.

Therefore, the volume of the larger cone (V2) is 4^3 = 64 times the volume of the smaller cone (V1).

Given that the volume of the smaller cone (V1) is 1 m^3, the volume of the larger cone (V2) is 64 * 1 m^3 = 64 m^3.

The figures below are similar.1 m3 mV1 = 64 m3 V2 = ?What is the volume of the larger cone?

Question

The figures below are similar.

Solution

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