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Arrange in increasing order of ionic radii- O, C, F, Cl, BrF, O, C, Cl, BrF, C, O, Cl, BrF, Cl, Br, O, CC, O, F, Cl, Br

Question

Arrange in increasing order of ionic radii-

O, C, F, Cl, BrF, O, C, Cl, BrF, C, O, Cl, BrF, Cl, Br, O, CC, O, F, Cl, Br

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Solution

The question seems to be a bit confusing as it repeats elements and also includes "BrF" and "CC" which are not single ions, but compounds or repetitions of an element. However, if we consider only the single ions, the order of increasing ionic radii generally follows the order of their positions in the periodic table.

The ionic radius increases as you move down a group (column) in the periodic table because each row adds a new electron shell. Also, the ionic radius decreases as you move across a period (row) from left to right, due to the increasing nuclear charge which pulls the electrons closer to the nucleus.

Given the ions O, C, F, Cl, and Br, the order of increasing ionic radii would be:

C- < O- < F- < Cl- < Br-

This order is based on the fact that Carbon (C) is in the second period of the periodic table, Oxygen (O) and Fluorine (F) are in the second period, and Chlorine (Cl) and Bromine (Br) are in the third and fourth periods respectively.

Please note that this is a simplified explanation and actual ionic sizes can be affected by other factors such as ionization state and the particular isotope of the element.

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