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Anane the bonds, in order of increasing ionic character in the nolecules: 1LiF, K,0, N, SO, and CIF,:

Question

Anane the bonds, in order of increasing ionic character in the molecules:

  1. LiF
  2. K
  3. O
  4. N
  5. SO
  6. CIF
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Solution

To determine the order of increasing ionic character in the given molecules, we need to compare the electronegativity difference between the atoms involved in each bond.

  1. LiF: Lithium (Li) is a metal and fluorine (F) is a nonmetal. The electronegativity difference between Li and F is relatively large, indicating a highly ionic bond. Therefore, LiF has the highest ionic character.

  2. K2O: Potassium (K) is a metal and oxygen (O) is a nonmetal. The electronegativity difference between K and O is smaller than that of Li and F, but still significant. Thus, K2O has a moderate ionic character.

  3. N2: Nitrogen (N) is a nonmetal and forms a covalent bond with itself. Covalent bonds involve the sharing of electrons, so N2 has the least ionic character among the given molecules.

  4. SO2: Sulfur (S) is a nonmetal and oxygen (O) is also a nonmetal. The electronegativity difference between S and O is smaller than that of K and O, indicating a lower ionic character.

  5. ClF: Chlorine (Cl) is a nonmetal and fluorine (F) is also a nonmetal. The electronegativity difference between Cl and F is relatively small, suggesting a lower ionic character compared to Li and F.

Therefore, the order of increasing ionic character in the given molecules is: N2 < SO2 < ClF < K2O < LiF.

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