Cl2+NaOh(hot& concentration) products what is highest oxidation state of Cl in product

To determine the highest oxidation state of chlorine in the product, we need to consider the reaction between Cl2 and NaOH under hot and concentrated conditions.

1. Write the balanced chemical equation for the reaction: Cl2 + 2NaOH → NaCl + NaClO + H2O

2. Identify the oxidation states of each element in the reactants and products: In Cl2, chlorine has an oxidation state of 0. In NaOH, sodium has an oxidation state of +1, oxygen has an oxidation state of -2, and hydrogen has an oxidation state of +1. In NaCl, sodium has an oxidation state of +1 and chlorine has an oxidation state of -1. In NaClO, sodium has an oxidation state of +1, oxygen has an oxidation state of -2, and chlorine has an unknown oxidation state.

3. Determine the oxidation state of chlorine in NaClO: Since the overall charge of NaClO is 0, the sum of the oxidation states of each element must equal 0. The oxidation state of sodium is +1, and the oxidation state of oxygen is -2. Let the oxidation state of chlorine in NaClO be x. Therefore, the equation becomes: (+1) + (-2) + x = 0. Solving for x, we find that the oxidation state of chlorine in NaClO is +3.

4. Conclusion: The highest oxidation state of chlorine in the product is +3, which is found in NaClO.