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Draw a circuit to implement 𝑌 = 𝐴𝐵 + 𝐴𝐵𝐶 + 𝐴̅ 𝐵)𝐶̅ using a decoder. Label thedecoder pins appropriately

Question

Draw a circuit to implement 𝑌 = 𝐴𝐵 + 𝐴𝐵𝐶 + 𝐴̅ 𝐵)𝐶̅ using a decoder.

Label the decoder pins appropriately.

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Solution

To implement the given Boolean expression Y = AB + ABC + \overline{A}B)C̅ using a decoder, we will follow these steps:

1. Break Down the Problem

  1. The expression can be simplified if needed and can be implemented using a 3-to-8 decoder.
  2. We'll determine the inputs and how they relate to the output.

2. Relevant Concepts

  • A 3-to-8 decoder takes 3 input signals and produces 8 output signals corresponding to the binary values of the input.
  • The output pins will be active high for the corresponding binary encoded input.

3. Analysis and Detail

  1. Identify the variables:

    • Inputs: A,B,C A, B, C
    • Outputs: There will be 8 outputs corresponding to combinations of A,B,C A, B, C (000 to 111).
  2. The relevant minterms from the expression Y Y :

    • AB AB corresponds to minterms 110 110 (where A=1,B=1,C=0 A=1, B=1, C=0 ) and 111 111 (where A=1,B=1,C=1 A=1, B=1, C=1 ).
    • ABC ABC is already part of AB AB when C C is also true, hence does not introduce additional outputs.
    • AB \overline{A}B corresponds to B B when A=0 A=0 , which describes minterms 010 010 (where A=0,B=1,C=0 A=0, B=1, C=0 ) and 011 011 (where A=0,B=1,C=1 A=0, B=1, C=1 ).
    • The expression indicates that we will need outputs from the decoder when C=0 C=0 .
  3. Based on these minterms, the active outputs from the decoder will be:

    • Output 2 2 (for minterm 010 010 )
    • Output 3 3 (for minterm 011 011 )
    • Output 6 6 (for minterm 110 110 )
    • Output 7 7 (for minterm 111 111 )

4. Verify and Summarize

The circuit will use outputs D2,D3,D6,D7 D2, D3, D6, D7 of the decoder to derive Y Y by connecting them to an OR gate.

Final Answer

Here's a sample circuit representation:

Decoder (3-to-8)
Inputs: A (pin 1), B (pin 2), C (pin 3)
Outputs: D0 (000), D1 (001), D2 (010), D3 (011), D4 (100), D5 (101), D6 (110), D7 (111)

Connections:
- D2 (from A=0, B=1, C=0)
- D3 (from A=0, B=1, C=1)
- D6 (from A=1, B=1, C=0)
- D7 (from A=1, B=1, C=1)

Final Output:
Y = D2 + D3 + D6 + D7

Circuit Diagram

  A ------|   |                      Y
  B ------|   |--------------------|   |
  C ------|   |        OR         |   |
          | 3-to-8 Decoder       |   |
          |   |                    ---
          |   |                    |
          ---------------------------  

This circuit will successfully implement the function Y=AB+ABC+ABC Y = AB + ABC + \overline{A}BC using a decoder.

This problem has been solved

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