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A normal QUEUE, if implemented using an array of size MAX-SIZE, gets full whenFront = (rear + 1)% MAX-SIZERear = MAX-SIZE – 1Rear = FrontFront = rear + 1;

Question

A normal QUEUE, if implemented using an array of size MAX-SIZE, gets full when:

  • Front = (rear + 1) % MAX-SIZE
  • Rear = MAX-SIZE – 1
  • Rear = Front
  • Front = rear + 1;
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Solution

The statement seems to be a bit confusing, but it appears to be discussing the implementation of a queue data structure using an array.

A queue is a First-In-First-Out (FIFO) data structure, meaning that the first element added to the queue will be the first one to be removed.

In an array-based implementation of a queue, we typically maintain two indices, front and rear, to keep track of the start and end of the queue.

  1. Front is where we remove elements from the queue (dequeue operation).
  2. Rear is where we add elements to the queue (enqueue operation).

Now, let's break down the conditions mentioned:

  1. Front = (rear + 1)% MAX-SIZE: This condition checks if the queue is full. The modulus operation ensures we loop back to the start of the array when we reach the end. If the front is one position ahead of the rear (considering the looping), it means the queue is full.

  2. Rear = MAX-SIZE – 1: This condition checks if the rear has reached the end of the array. If so, and if the front is not at 0, we can still add elements to the start of the array.

  3. Rear = Front: This condition checks if the queue is empty. If the front and rear are at the same position, it means no elements are in the queue.

  4. Front = rear + 1: This condition seems to be similar to the first one and might be used to move the front one position ahead when an element is dequeued.

Please note that the exact conditions can vary based on the specific implementation of the queue.

This problem has been solved

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