Calculate the electrode potential of Cr3+/Cr electrode at [Cr3+] = 0.001 M.Given: Cr3+ + 3e– Cr E° = – 0.74 V
Question
Calculate the electrode potential of Cr3+/Cr electrode at [Cr3+] = 0.001 M.
Given:
Cr^{3+} + 3e^{-} \rightarrow Cr \
E° = -0.74 \, V
Solution
To calculate the electrode potential of the Cr3+/Cr electrode at [Cr3+] = 0.001 M, we can use the Nernst equation:
E = E° - (0.0592/n) * log([Cr3+]/[Cr])
Given that E° = -0.74 V, [Cr3+] = 0.001 M, and we are looking for the electrode potential of Cr3+/Cr, we can substitute these values into the equation:
E = -0.74 V - (0.0592/3) * log(0.001/[Cr])
Simplifying further:
E = -0.74 V - (0.01973) * log(0.001/[Cr])
Now, you need to provide the value of [Cr] in order to calculate the electrode potential.
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