When dividing the polynomial by long division, identify the numeric remainder.(–2x3 – 4x2  + 5) ÷÷ (x + 3)

Step 1: Set up the long division. Write the dividend (-2x^3 - 4x^2 + 5) inside the long division symbol and the divisor (x + 3) outside.

Step 2: Divide the first term of the dividend (-2x^3) by the first term of the divisor (x). This gives you -2x^2. Write this above the long division line.

Step 3: Multiply the divisor (x + 3) by the term you just found (-2x^2). Write the result (-2x^3 - 6x^2) under the first two terms of the dividend and draw a line under it.

Step 4: Subtract the result from Step 3 from the first two terms of the dividend. This gives you 2x^2 + 5. Write this under the line.

Step 5: Bring down the next term from the dividend (there are no more terms to bring down in this case).

Step 6: Repeat the process. Divide the first term of the new dividend (2x^2) by the first term of the divisor (x). This gives you 2x. Write this above the long division line, next to -2x^2.

Step 7: Multiply the divisor (x + 3) by the term you just found (2x). Write the result (2x^2 + 6x) under the new dividend and draw a line under it.

Step 8: Subtract the result from Step 7 from the new dividend. This gives you -6x + 5.

Step 9: Repeat the process again. Divide the first term of the new dividend (-6x) by the first term of the divisor (x). This gives you -6. Write this above the long division line, next to -2x^2 + 2x.

Step 10: Multiply the divisor (x + 3) by the term you just found (-6). Write the result (-6x - 18) under the new dividend and draw a line under it.

Step 11: Subtract the result from Step 10 from the new dividend. This gives you 23.

So, the numeric remainder when dividing the polynomial (-2x^3 - 4x^2 + 5) by (x + 3) is 23.