Knowee
Questions
Features
Study Tools

The adjoining figure is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB = 27°, then find ∠OBC.

Question

The adjoining figure is a rectangle whose diagonals AC and BD intersect at O. If OAB=27\angle OAB = 27^\circ, then find OBC\angle OBC.

🧐 Not the exact question you are looking for?Go ask a question

Solution

In a rectangle, the diagonals are equal in length and bisect each other. This means that they cut each other in half at the point of intersection, which is point O in this case.

Since the diagonals bisect each other, this means that ∠OAB = ∠OBA. Given that ∠OAB = 27°, this means that ∠OBA is also 27°.

In a rectangle, the sum of the angles is 180°. Therefore, ∠OBC = 180° - ∠OBA = 180° - 27° = 153°.

So, ∠OBC = 153°.

This problem has been solved

Similar Questions

The adjoining figure is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB = 27°, then find ∠OBC.

The diagonals of rectangle ABCD intersect at a point O. If ∠COD is 78°, then find ∠OAB.

7 In the given figure, O is the centre of the circle, ∠AOB = 600 and ∠CDB= 900. Find ∠OBC

Lines AC and BD intersect at point O.If m∠AOD = (10x − 7)° and m∠BOC = (7x + 11)°, what is m∠BOC?Group of answer choices53°89°6°106°

In the given figure, ABCD is a rhombus with ÐABC = 56°. Determine ÐACD.CDOA B(1) 31° (2) 45° (3) 62° (4) 90°

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.