What will be the output of the following Python code?def ct(): y=76 print(x)y=+2ct()OptionsError787476
Question
What will be the output of the following Python code?
def ct():
y=76
print(x)
y=+2
ct()
Options
- Error
- 78
- 74
- 76
Solution
To determine the output of the provided Python code, let's break down the code step by step, identifying potential issues and understanding the flow.
1. Break Down the Problem
The function ct
is defined, and inside it, a variable y
is assigned the value 76
. The code then tries to print x
, which is not defined within the function. Lastly, y
is redefined using y=+2
.
2. Relevant Concepts
In Python, when you reference a variable, Python looks for its definition in the following order:
- Local scope (inside the function)
- Enclosing scope (if it is nested)
- Global scope (if not found)
Since x
is not defined anywhere before the print(x)
line within ct
, this will lead to a NameError
.
3. Analysis and Detail
Here’s the flow of the program:
- Define Function:
def ct():
begins the definition of the functionct
. - Assign y:
y = 76
assigns the value 76 toy
. - Print x:
print(x)
attempts to printx
, butx
is not defined, leading to an error. - Assign y again:
y = +2
will not be executed due to the error encountered in the previous step.
4. Verify and Summarize
Since the attempt to print x
results in a NameError
(because x
has not been defined), the output of this code will be an error message indicating that x
is not defined.
Final Answer
The output of the code will be a NameError
indicating that x
is not defined, as x
has not been declared or assigned any value within the function ct
.
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