The correct answer is "Error".

Here's the step-by-step explanation:

1. The function `ct()` is defined, which has a local variable `y` with a value of 76.
2. Inside the function, `print(x)` is called. However, `x` is not defined anywhere in the code, neither as a global nor as a local variable.
3. Therefore, when the function `ct()` is called, it will try to print the value of `x`, but since `x` is not defined, Python will raise a `NameError` saying that `x` is not defined.
4. The line `y=+2` outside the function does not affect the function because `y` inside the function is a local variable. Changes to the global `y` do not affect the local `y`.

So, the output of the code will be an error.

Question

The correct answer is "Error".

Here's the step-by-step explanation:

1. The function `ct()` is defined, which has a local variable `y` with a value of 76. 
2. Inside the function, `print(x)` is called. However, `x` is not defined anywhere in the code, neither as a global nor as a local variable. 
3. Therefore, when the function `ct()` is called, it will try to print the value of `x`, but since `x` is not defined, Python will raise a `NameError` saying that `x` is not defined. 
4. The line `y=+2` outside the function does not affect the function because `y` inside the function is a local variable. Changes to the global `y` do not affect the local `y`.

So, the output of the code will be an error.

Knowee AI · Accepted Answer

The correct answer is "Error".

Here's the step-by-step explanation:

1. The function `ct()` is defined, which has a local variable `y` with a value of 76. 
2. Inside the function, `print(x)` is called. However, `x` is not defined anywhere in the code, neither as a global nor as a local variable. 
3. Therefore, when the function `ct()` is called, it will try to print the value of `x`, but since `x` is not defined, Python will raise a `NameError` saying that `x` is not defined. 
4. The line `y=+2` outside the function does not affect the function because `y` inside the function is a local variable. Changes to the global `y` do not affect the local `y`.

So, the output of the code will be an error.

Select the correct answerWhat will be the output of the following Python code?def ct(): y=76 print(x)y=+2ct()OptionsError787476

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