E and F are mutually exclusive events. P(E) = 0.4; P(F) = 0.5. P(E∣F) = ___________.Question 3Answera.0b.0.25c.2

Break Down the Problem

1. We have two mutually exclusive events, E and F.
2. We need to find $P(E \mid F)$.

Relevant Concepts

1. For mutually exclusive events, $P(E \cap F) = 0$.
2. The conditional probability formula is given by: $P(E \mid F) = \frac{P(E \cap F)}{P(F)}$

Analysis and Detail

1. Since events E and F are mutually exclusive, therefore, they cannot both occur at the same time, hence: $P(E \cap F) = 0$
2. Given $P(F) = 0.5$, we can substitute $P(E \cap F)$ into the conditional probability formula: $P(E \mid F) = \frac{0}{0.5} = 0$

Verify and Summarize

1. Since the calculation yields $P(E \mid F) = 0$, it confirms that if F occurs, E cannot occur as they are mutually exclusive.

Final Answer

$P(E \mid F) = 0$

Thus, the correct answer is a. 0.