An object weighs 0.250 kgf in air, 0.150 kgf in water and 0.125 kgf in an oil. Calculate

1. Break Down the Problem

We need to calculate the weight of the object in three different mediums: air, water, and oil. The weights are given in kilograms-force (kgf), and we can also determine the specific weight of the object as well as the buoyant force it experiences in each medium.

2. Relevant Concepts

The weight of an object in a fluid can be calculated using the buoyancy principle, which states that the buoyant force exerted on an object immersed in a fluid is equal to the weight of the fluid displaced by the object.

1. Weight in Air ($W_{air}$): 0.250 kgf
2. Weight in Water ($W_{water}$): 0.150 kgf
3. Weight in Oil ($W_{oil}$): 0.125 kgf

The buoyant force ($F_b$) can be calculated as: $F_b = W_{air} - W_{fluid}$ where $W_{fluid}$ is the weight of the object in the fluid (either water or oil).

3. Analysis and Detail

1. Buoyant Force in Water: $F_b^{water} = W_{air} - W_{water} = 0.250 \, \text{kgf} - 0.150 \, \text{kgf} = 0.100 \, \text{kgf}$

2. Buoyant Force in Oil: $F_b^{oil} = W_{air} - W_{oil} = 0.250 \, \text{kgf} - 0.125 \, \text{kgf} = 0.125 \, \text{kgf}$

4. Verify and Summarize

• The buoyant force in water is 0.100 kgf, and it is greater than that in oil, which is 0.125 kgf. This confirms that the object experiences different buoyancy in these two fluids.
• We can represent the findings in a summarized manner:

Final Answer

• Weight in Air: $W_{air} = 0.250 \, \text{kgf}$
• Buoyant Force in Water: $F_b^{water} = 0.100 \, \text{kgf}$
• Buoyant Force in Oil: $F_b^{oil} = 0.125 \, \text{kgf}$