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(-10,2) is point of y =f(¹/₂x+3)-2,      then point of y==f(-¹/₂x+3)-2 is*(-10,-2)(10,-2)(10,2)(-10,2)

Question

(-10,2) is point of y = f(12x+3\frac{1}{2}x+3) - 2,

then point of y = f(12x+3-\frac{1}{2}x+3) - 2 is *(-10,-2)(10,-2)(10,2)(-10,2)

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Solution

The point on the function y = f(1/2x + 3) - 2 is (-10, 2). This means when x = -10, y = 2.

Now, we want to find the corresponding point on the function y = f(-1/2x + 3) - 2.

The x-coordinate changes sign because of the negative sign in front of the 1/2 in the function. So, the x-coordinate in the new function will be -(-10) = 10.

The y-coordinate remains the same because the -2 at the end of the function does not change. So, the y-coordinate in the new function will still be 2.

Therefore, the corresponding point on the function y = f(-1/2x + 3) - 2 is (10, 2).

This problem has been solved

Similar Questions

(-10,2) is point of y =f(¹/₂x+3)-2,      then point of y==f(-¹/₂x+3)-2 is*(-10,-2)(10,-2)(10,2)(-10,2)

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