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A certain laser transition emits 6.0 x 1015 quanta per second per square meter of λ = 662.6 nm.What is the power output in joule per second per square meter?

Question

A certain laser transition emits 6.0 x 10^15 quanta per second per square meter of λ=662.6 nm \lambda = 662.6 \text{ nm} . What is the power output in joule per second per square meter?

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Solution

To calculate the power output in joules per second per square meter, we first need to convert the wavelength from nanometers to meters.

1 nm = 1 x 10^-9 m

So, λ = 662.6 nm = 662.6 x 10^-9 m

Next, we use the formula for the energy of a photon, which is given by Planck's equation:

E = h * c / λ

where h is Planck's constant (6.626 x 10^-34 joule seconds), c is the speed of light (3.0 x 10^8 m/s), and λ is the wavelength in meters.

E = (6.626 x 10^-34 J*s) * (3.0 x 10^8 m/s) / (662.6 x 10^-9 m) E = 3.00 x 10^-19 J

This is the energy of one photon. The laser emits 6.0 x 10^15 photons per second per square meter, so the power output is:

P = E * number of photons P = (3.00 x 10^-19 J) * (6.0 x 10^15 photons/s*m^2) P = 1.8 W/m^2

So, the power output is 1.8 joules per second per square meter.

This problem has been solved

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