Knowee
Questions
Features
Study Tools

How many different permutations can be made from the letters in the word “CHICHARITO”?Question 6Answera.453,600b.1,814,400c.3,628,800d.907,200

Question

How many different permutations can be made from the letters in the word CHICHARITO?

Question 6
Answer

  • a. 453,600
  • b. 1,814,400
  • c. 3,628,800
  • d. 907,200
🧐 Not the exact question you are looking for?Go ask a question

Solution

1. Break Down the Problem

We need to calculate the number of different permutations of the letters in the word "CHICHARITO". The word has repeating letters, so we need to account for these repetitions in our calculation.

2. Relevant Concepts

The formula for calculating permutations of letters, taking into account repetitions, is given by:

P=n!n1!n2!nk! P = \frac{n!}{n_1! \cdot n_2! \cdot \ldots \cdot n_k!}

Where:

  • n n is the total number of letters,
  • n1,n2,,nk n_1, n_2, \ldots, n_k are the frequencies of the distinct letters.

3. Analysis and Detail

  1. Count Total Letters:

    • The word "CHICHARITO" has 10 letters.
  2. Count Frequencies of Each Letter:

    • C: 2
    • H: 2
    • I: 2
    • A: 1
    • R: 1
    • T: 1
    • O: 1
  3. Substitute Values into the Formula:

    • Total letters n=10 n = 10
    • Frequencies: nC=2 n_C = 2 , nH=2 n_H = 2 , nI=2 n_I = 2 , nA=1 n_A = 1 , nR=1 n_R = 1 , nT=1 n_T = 1 , nO=1 n_O = 1

    Plugging these into the formula gives us:

P=10!2!2!2!1!1!1!1! P = \frac{10!}{2! \cdot 2! \cdot 2! \cdot 1! \cdot 1! \cdot 1! \cdot 1!}

4. Verify and Summarize

  1. Calculate the Factorials:

    • 10!=3,628,800 10! = 3,628,800
    • 2!=2 2! = 2 , therefore 2!2!2!=2×2×2=8 2! \cdot 2! \cdot 2! = 2 \times 2 \times 2 = 8
    • 1!=1 1! = 1 , hence these contribute 1 1 each.
  2. Final Calculation:

    • Substituting into our equation:

P=3,628,8008=453,600 P = \frac{3,628,800}{8} = 453,600

Final Answer

The number of different permutations that can be made from the letters in the word “CHICHARITO” is 453,600, which corresponds to option a. 453,600.

This problem has been solved

Similar Questions

Find the number of arrangements taking all the letters of the word  CONTACTans.1220126014001136

How many ways are there to permute the 8 letters A, B, C, D, E, F, G, H so that A is not at the beginning and H is not at the end?

There are 6 letters for 3 envelopes. In how many different ways can the envelopes be filled?Choices:- 120 130 100 110

How many 3 letter words can you make from the letters A,B,C and D, where letters cannot be repeated and are in alphabetical order?

How many distinct arrangements can be made from the letters of the word “MAHIRAP”?

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.